Question

Find the two parallel sides of a trapezium whose area is 1.6 m, altitude is 10 dm
and one of the parallel sides is longer than the other by 8 dm.​

Answer 1

Answer:

Step-by-step explanation:

Given :-

Area of trapezium = 1.6 sq m

Altitude, h = 10 dm = 1 m

To Find :-

The two parallel sides.

Formula to be used :-

Area of trapezium

Solution :-

Let one of the parallel sides be x

And the other side be (x + 0.8) m

According to the Question

Area of trapezium, A = (1/2) × h × (a + b)

⇒ 1.6 = (1/2) × 1 × (x + x + 0.8)

⇒ 3.2 = 2x + 0.8

⇒ 2x = 3.2 - 0.8 = 2.4

⇒ x = 1.2 m

1st Side = 1.2 m

2nd Side = (x + 0.8) = 2 m

Hence, the parallel sides are 1.2 m and 2 m.

Answer 2

Answer:

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Given

area of trapezium = 1.6 sq m

Altitude, h = 10 dm = 1 m

Let one of the parallel sides be x then the other side will be (x + 0.8) m

Recall that area of trapezium, A = (1/2) x h x (a + b)

1.6 = (1/2) × 1 × (x + x + 0.8)

3.2 = 2x + 0.8

2x = 3.2 - 0.8 = 2.4

Therefore, x = 1.2 m

(x + 0.8) = 2 m

Thus the parallel sides are 1.2m and 2 m