Question

find the two parallel sides of a Trapezium whose area is 1.6 m square altitude is 10 dm and one of the parallel side is longer than the other by 8dm

Answer 1

area of trapezium= 1/2×(add of 2parallel side) ×h
1.6=1/2×(x+0.8+x)×1
1.6×2=2x+0.8
3.2= 2x+0.8
3.2-0.8=2x
2.4=2x
x=1.2
so 1 parallel side is x=1.2m=12dm
greater parallel side isx+0.8=1.2+0.8
2m=20dm

Answer 2

$1.6 {m}^{2} = \frac{1}{2} (x + x + 0.8m) \times 1m$

$1.6 {m}^{2} \times 2 = x + x + 0.8$

$2.12 = 2x + 0.8$

$2.12m - 0.8m = 2x$

$2.4m = 2x$

$\dfrac{2.4m}{2} = x$

$1.2 = x$