find the two parallel sides of a trapezium whose area is 1.6 dm, altitude is 10 dm and one of the parallel sides is longer than the other by 8 dm
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Let the 1st parallel side be x
So the other parallel side=x+8 dm
Area of the trapezium=1.6 dm
Altitude of the trapezium=10 dm
=1/ 2×10 dm×(x+8x) dm= 10 dm
=5×9x = 10
=9x =10/5
=9x = 2
=x = 2/9
So 1st parallel side=2/9dm
Hence 2nd parallel side= x+8dm
=2/9 dm+8dm
=74/9dm
So the other parallel side=x+8 dm
Area of the trapezium=1.6 dm
Altitude of the trapezium=10 dm
=1/ 2×10 dm×(x+8x) dm= 10 dm
=5×9x = 10
=9x =10/5
=9x = 2
=x = 2/9
So 1st parallel side=2/9dm
Hence 2nd parallel side= x+8dm
=2/9 dm+8dm
=74/9dm
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