Question

Find the two parallel sides of a trapezium whose area is 160 dm, altitude is 10 dm
and one of the parallel sides is longer than the other by 8 dm.​

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manoj572779

manoj572779

28.07.2019

Math

Secondary School

+5 pts

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find the two parallel sides of trapezium whose area is 1.6 metre square altitude is 10 DM and one of the parallel side is longer than the other by 8dm.

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THE BRAINLIEST ANSWER!

given :-

area of the trapezium = 1.6m²

we know that, 1m² = 100dm²

➡ 1.6m² = 160dm²

altitude of the trapezium = 10dm

ATQ,

one of the parallel sides of the trapezium is 8dm more than the other one.

let the smaller parallel side be x

therefore the longer parallel side = x + 8

formula to find the area of a trapezium = 1/2 × h(b1 + b2)

where h is the altitude and b1 and b2 are the parallel sides Respectively.

➡ 1/2 × h (b1 + b2) = 160dm²

➡ 1/2 × 10(x + x + 8) = 160dm²

➡ 5(2x + 8) = 160dm²

➡ 10x + 40 = 160dm²

➡ 10x = 160 - 40

➡ x = 120/10

➡ x = 12dm

hence, the parallel sides are :-

b1 = x = 12dm

b2 = x + 8 = 12 + 8 = 20dm

Step-by-step explanation:

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