Question

Find the two parallel sides of a trapezium whose area is about 1.6 m², altitude is 10dm and one of the parallel sides is longer than the other by 8dm.​

Answer 1

Step-by-step explanation:

Given area of trapezium = 1.6 sq m

Altitude, h = 10 dm = 1 m

Let one of the parallel sides be x then the other side will be (x + 0.8) m

Recall that area of trapezium, A = (1/2) * h * (a + b)

=> 1.6 = (1/2) * 1 * (x + x + 0.8)

=> 1.6 * 2 = x + x + 0.8)

=> 3.2 = 2x + 0.8

=> 2x = 3.2 - 0.8 = 2.4

Therefore, x = 1.2 m

and x + 0.8 = 1.2 + 0.8 = 2 m

Thus, the parallel sides are 1.2 m and 2 m

 

Answer 2

Step-by-step explanation:

Given:-

Area of trapezium = 1.6 sq m

Altitude, h = 10 dm = 1 m

To Find :-

The two parallel sides.

Formula to be used :-

Area of trapezium

Solution :-

Let one of the parallel sides be x

And the other side be (x + 0.8) m

According to the Question

Area of trapezium, A = (1/2) × h × (a + b)

⇒ 1.6 = (1/2) × 1 × (x + x + 0.8)

⇒ 3.2 = 2x + 0.8

⇒ 2x = 3.2 - 0.8 = 2.4

⇒ x = 1.2 m

1st Side = 1.2 m

2nd Side = (x + 0.8) = 2 m

Hence, the parallel sides are 1.2 m and 2 m.