Question

find the two parallel sides of trapezium whose area is 1.6 sq.m . altitude is 10dm and one parallel side is longer then the other by 8dm​

Answer 1

Answer:

apply the formula of area of trapezium=(sum of parallel side)*altitude

now put the values and let one parallel side be =x

and other =x+8

Answer 2

Step-by-step explanation:

area of the given trapezium =1.6 sq.m

given altitude is =10dm

one parallel side is longer than other by =8dm

area of trapezium= 1/2(a+b)h

1.6sq m= 1/2(x+8xdm)10

1.6 = 10x/2+80/2

1.6sq.m=5x+40

1.6sq .m-40=5x

-39.6sq m=5x

-39.6/5sq.m=x

7.9sq.m=x

first parallel side =7.9dm

another=7.9+8dm=15.9dm.