Question

Find the two parallel sides of trapezium whose area is 1.6 m square altitude is 10 dm and one of the parallel sides longer than other by 8dm?

Answer 1

area of trapezuim=1/2*(sum of parallel sides)*height
1/2*{x+(x+8)}*10=1600                  [because 1.6m=1600dm]
1/2 * [2x+8] * 10=1600
[2x+8] * 5=1600
10x+200=1600
10x=1600-200=1400
x=1400/10
x=140dm
sides of trapezium=x=140dm=14m
                               x+8=140+8=148dm=14.8m