Question

find the two positive numbers whose squares have the different 48 and sum of number is 12​

Answer 1

Answer:

8,4

Step-by-step explanation:

8+4is 12 and 8*8is48

Answer 2

Let the numbers be x and y

${x}^{2} - {y}^{2} = 48$

x+ y = 12

(x+y)( x-y)= 48

12 (x-y)= 48

x-y = 4

x+ y = 12

Adding above equations we get

2x = 16

x = 8

x = 8 y = 4

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