find the two roots of
x^2 + 2√2x - 6
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√2 and -3√2
Step-by-step explanation:
GIVEN:
• A quadratic equation: x²+2√2x-6
TO FIND:
• Two Roots of the given equation.
SOLUTION:
Let's solve this method by factorisation method.
➠x²+2√2x-6=0
Here, we are going to split the middle term: 2√2x
2√2x can be splitted as 3√2x-√2x in which,
• When we subtract, 3√2x-√2x, we get the middle term = 2√2x
• When we multiply, 3√2x × -√2x, we get -6x²
➠x²+2√2x-6=0
➠x²+3√2x-√2x-6=0
On taking x and -√2 as common,
➠x(x+3√2)-√2(x+3√2)=0
➠(x-√2)(x+3√2)=0
➠x-√2 = 0 , x+3√2 = 0
➠x = √2, -3√2
Hence, the two roots of the given equation are √2 and -3√2.
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