Math, asked by utkarshamodak2010, 2 months ago

Find the two sides of a triangle whose perimeter is 32 cm, one side is 11 cm and difference of

other two sides is 5 cm.​

Answers

Answered by vedantihiwase
0

Step-by-step explanation:

Triangle

Solve for 

side

a

=

?

cm

b

Base

cm

c

Side

cm

P

Perimeter

cm

Attachments:
Answered by makhijanikrish
0

Answer:

8 and 13

Step-by-step explanation:

perimeter = 32

then x + y + z=32    (where x , y ,z are the sides of the triangle)

x=11

y + z = 21

y-z = 5

Therefore, y = 5+z   (equation 1)

5+z+z=21    By (1)

2z=16

z=8

y=13

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