find the two specific heats
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Let the specific heats are x and y
Then x-y=5000 Kg-1K-1----(1)
x/y= 1.6
x=1.6y
Now putting value of x in (1) we get
1.6y-y=5000
0.6y=5000
y=5000/0.6
=8333.33 Kg-1K-1
again from(1)
x-8333.33=5000
x=5000+8333.33=13333.33 Kg-1K-1
Anonymous:
ok always welcome
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