find the type of quadrilateral , if its vertices are (1, 4), (-5, 4), (-5, -3), (1,-3)
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Answered by
2
Answer:
it is rectangle shaped
Answered by
3
1,4=A
-5,4=B
-5,-3=C
1,-3=D
Now,
AB=√(1-(-5))^2+(4-4)^2
=√36+0
=6
BC=√(-5-(-5))^2+(4-(-3)^2
=√0+49
=7
DC=√(-5-1)^2+(-3-(-3))^2
=√36+0
= 6
DA=√(1-1)^2+(-3-4)^2
=√0+49
=7
These are the sides of quadrilateral
Now,Diagonals AC and BD
AC=√(1-(-5))^2+(4-(-3))^2
=√36+49
=√85
BD=√(-5-1)^2+(4-(-3))^2
=√36+49
=√85
As we can see Diagonals are equal
Hence,The quadrilateral is rectangle
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