Question

find the type of roots of the given equation x^2-23x +120=0
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Answer 1

ANSWER:

${x}^{2} - 23x + 120 = 0$

$a = 1$

$b = 23$

$c = 120$

$disc. \: = b^{2} - 4ac$

$disc. \: = (23)^{2} - 4(1)(120)$

$disc. \: = 529 - 480$

$disc. \: = 49$

$disc. \: = {7}^{2}$

As discriminant of the given equation is a perfect square and greater than zero

So , roots of this equation are rational (real) and unequal .