Question

find the unit digit 1!^1+2!^2+3!^3..........+10!^10. Please provide step by step explaination...​

Answer 1

Answer:

Here's the answer:

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1! + 2! + 3! + 4! + …… + 99!

1! = 1

2! = 2

3! = 6

4! = 24

5! = 120

From 5!, the numbers do not contribute to unit digit as the product contains at least one 2 and 5 resulting in 0 as the last digit in factorial Value.

•°• If we find the sum of these factorials, it will required unit digit

•°• Sum of these factorials = 1 + 2 + 6 + 24 + 0

= 33

Here, Unit digit = 3 in the resultant sum

•°• Required Unit digit = 3

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