find the unit digit of 8 to the power 243
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Hey Devansh,
Let's learn cyclicity of 8 first,
Unit digit of
8^(4k)=_6,
8^(4k+1)=_8,
8^(4k+2)=_4
8^(4k+3)=_2.
Now,8^243 On dividing the power 243by 4, remainder we get is 3.
So, it can be written in the form of
8^(4k+3) .And we know that unit digit of 8^(4k+3) =_2.
So, unit digit of 8^(243) is 2.
Hope it helps
Let's learn cyclicity of 8 first,
Unit digit of
8^(4k)=_6,
8^(4k+1)=_8,
8^(4k+2)=_4
8^(4k+3)=_2.
Now,8^243 On dividing the power 243by 4, remainder we get is 3.
So, it can be written in the form of
8^(4k+3) .And we know that unit digit of 8^(4k+3) =_2.
So, unit digit of 8^(243) is 2.
Hope it helps
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