Question

find the unit digit of the given expression:(216)^1000×(625)^2000×(514)^3000

Answer 1

Given,

(216)^1000 = The unit's place is 6.

(625)^2000 = The unit's place is 5.

(514)^3000 = The unit's place is 6.

Now, On multiplying three expressions unit's place, we get

6 * 5 * 6 = 180(Unit's place is 0).


Therefore the unit's digit of (216)^1000 * (625)^2000 * (514)^3000 = 0.


Hope this helps!

Answer 2

Here, we have...
=============

$(216) {}^{1000}$

>> The unit's place of this number is 6

$(625) {}^{2000}$

>> The unit's place of this number is 5

$(514) {}^{3000}$

>>The unit's place of this number is 4

A/Q,

( 6*5*4) = 180

In the number above, we see that it's unit place is 0

So,

The unit digit of the given expression:-

(216)^1000×(625)^2000×(514)^3000 is 0

Hope it helps!!