Question

find the unit place in end result a)(123)³⁵⁶+(556)⁵⁶​

Answer 1

Step-by-step explanation:

${3}^{1} = 3$

${3}^{2} = 9$

${3}^{3} = 27$

${3}^{4} = 81$

${3}^{5} = 243$

every 5th chance 3 at unit place repeats

Now 356 ÷ 5 = 71 , remainder is 1

$so \: {123}^{356} \: will \: have \: 9 \: at \: unit \: place$

$similarly \: {556}^{56 \: } will \: have \: 6 \: at \: their \: unit \: place$

since 9 + 6 = 15 , therefore

5 will have the required digit at unit place.