Question

find the unit's digit in (264)^102+(264)^103

Answer 1

We know that:

= > 4^1 = 4

= > 4^2 = 16

= > 4^3 = 64

= > 4^4 = 256.


As, u can see When 4 has odd power, the unit digit is 4.

In the same way, when 4 has even power, the unit digit is 6.



Now,

Given Question is (264)^102 + (264)^103

(1) (264)^102

The units digit is 4^102

Here, the power is even, therefore the result is 6.


(2) (264)^103

Here the power is odd, therefore the result is 4.



Hence,

The units digit in (264)^102 + (264)^103

= > 6 + 4

= > 10

= > 0.



Hope this helps!