Question

Find the unit's digit of (125)^12 + (167)^13?
Select one:
a. 4
b. 1
C. 2
d. o​

Answer 1

Answer:

2

Step-by-step explanation:

units place of (125)^12 is 5

units place of (167)^13 is 7

5+7= 12

so units place is 12

Answer 2

Answer:

2

Step-by-step explanation:

(125)^12 + (167)^13

(125)^12=Last digit of 125 is 5

The cyclicity of 5 is 1

12/1=12

Remainder is 0

When the last digit is 5 and the remainder is zero

The unit is always 5.

(167)^13=Last digit of 167 is 7

The cyclicity of 7 is 4

13/4=12 Remainder is 1

7^1=7

(125)^12 + (167)^13=5+7=12

12 The last digit is unit digit

so, the answer is 2