Question

Find the unit tangent vector to any point on the curve r=(t^2+1)i+(4t-3)j+(2t^2-6t)k

Answer 1

Answer:

dR dr dr d2r a 0% er 3 dr dgr — I — >< — + r X X + r X — >< dt dt dt dt2 dt2 dt2 dt dt3 d? d? ... Find the unit tangent vector at any point on the curve x = t2 + 2, y = 4t — 5, z = 2t2 — 6t, where t is any variable. ... If r is the position vector of any point (x, y, 2) on the given curve, then r I xi + yj + zk —> A A_ A :> r =(t2+2)i + (4t—5)J + (2t2—6t)k —> The vector d_r is ... given curve. dt d—> Now 01—; : 2ti + 4}" +011 _ 6)]; _> and Gil—Z I J<2¢>2 +002 +(4t _ (5)2 :\/2012 —431 +52 I 245:2 _ 121+ 13 ...

Step-by-step explanation:

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