Find the unit vector in the direction of 3i^+4j^−12k^.
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Answered by
1
Answer: you
Explanation:unit vector = "a" vector/magnitude of a vector
3i+4j-12k/13
Answered by
3
Explanation:
let a vector= 3i^+4j^-12k^
|a|=√3²+4²+(-12)²
|a|=√9+16+144
|a|=√169
|a|=13
unit vector along vector a=3/13i^+4/13j^-12/13k^
good luck champ!
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