Find the unit vector in the direction of the vector 3i+4j
3i/5+4j/5
3i/5-4j/5
- 3i/5-4j/5
-3i/5+4j/5
Answers
Answered by
0
Explanation:
Let
a
=−3
i
+4
j
.
Then,
∣
a
∣=
2
2
+(−1)
2
=
5
Therefore,
A unit vector parallel to
a
is
a
=
∣
a
∣
a
.
a
=
5
1
(2
i
−
j
)=
5
2
i
−
5
1
j
Hence, required vector = 5
a
=5(
5
2
i
−
5
1
j
)=2
5
i
−
5
j
.
Similar questions