Question

find the unit vector in the direction of vector a equal to 2 i + 3 J + k​

Answer 1

Answer:

let v=2i+3j+k

unit vector=vector/ it's magnitude

|v|=(2^2+3^2+1^2)^1/2

|v|=(14)^1/2

unit vector of v=

$(2 \div \sqrt{14} )i + (3 \div \sqrt{14} )j + (1 \div \sqrt{14} )k$

Answer 2

Answer:

Given:

ā=2i+3j+k

Magnitude of ā=√2²+3²+1

|ā|=√4+9+1=√14

Unit vector in the direction of ā=ā/|ā|

â=2i+3j+k/√14

â=2/√14i+3/√14j+1/√14k

So, The unit vector in the direction of ā is

2/√14i+3/√14j+1/√14k

Step-by-step explanation:

Hope it helps......