Question

Find the unit vector of 5i+6j-k​

Answer 1

Answer:

$\sqrt{ {5}^{2} + {6}^{2} { - k}^{2} } \\ = \sqrt{25 + 36 - {k}^{2} } \\ = \sqrt{61 + {k}^{2} }$

hope this helps you

Answer 2

Explanation:

They are parallel or coinicidental vectors with different magnitudes. The angle between them is 0 deg. 5i-5j = 5(i-j) 3.5i-3.5j = 3.5(i-j)