Question

Find the unit vector of A= 3i+2j-5k

Answer 1

hey mate :-

Find the unit vector of A= 3i+2j-5k

Answer:-

given vector

A= 3i +2j -5k

so,

magnitude of A = √(x²+y²+z²)

where x= 3,y=2,z=-5

= √(3²+2²+(-5)²)

/ = √(9+4+25)

= √(38)

so,

unit vector = vector / magnitude of the vector

= (3i+2j-5k)/(√38)

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Answer 2

Explanation:

A =3i+2j+-5k

unit vector =A/A magnitude

* mag =√3+2+5

=√38

ut=3i+2j-5k/√38