Question

Find the unit vector of a =41 -j + 3k.​

Answer 1

Answer:

OK......

Explanation:

Find the unit vector of a =41 -j + 3k.

Answer 2

Answer:

unit vector = a/ mod a

a = 41-j+3k

mod a =

$\sqrt{41 {}^{2} + ( - 1) {}^{2} + 3 {}^{2} }$

$\sqrt{1681 + 1 + 9}$

$\sqrt{1691}$

unit vector =

$41 - j + 3k \div \sqrt{1691}$