Question

find the unit vector of A vector 4 icap- 3jcap+kcap​

Answer 1

Answer:

1/√26(4icap+3jcap+kcap)

Explanation:

magnitude of 4icap+3jcap+k cap is

√4²+3²+1²=√26

so the answer is 1/√26(4icap+3jcap+kcap)

Answer 2

Question :-

Find the unit vector of A vector 4i - 3j+ k

Solution :-

• First let us find magnitude of Vector A

$\sf\rightarrow |A| = \sqrt{4^{2} + 3^{2} + 1^{2} }$ = $\sf\sqrt{26}$

• We know that, unit vector of A = $\sf\frac{A}{|A|}$

$\sf\rightarrow Unit \ vector \ of \ A = \frac{4i - 3j + k}{\sqrt{26} }$

$\sf\rightarrow \frac{4}{\sqrt{26} } i - \frac{3}{\sqrt{26} } j + \frac{1}{\sqrt{26} } k$

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$\rightarrow$ Sathvik :)