Question

find the unit vector parallel to the vector. A= 3i + 6j - 2k

Answer 1

The unit vector parallel to this vector will be....

As they are parallel they have same inclination between them ...
so the unit vector will be ..

A cap = A vector / mod of A

there fore unit vector = 3i + 6j - 2k / square root of (3)^2 + (6)^2 + (-2)^2...

there fore the unit vector = 3i + 6j - 2k / under root 49
there fore unit vector = 3i + 6j - 2k /7....