Question

find the unit vector parallel to the vector A =3i+6j-2k

Answer 1

Hope this helps you.

Answer 2

Vector A = 3 i + 6 j - 2 k

Vector = Magnitude + Direction

First we need to find the magnitude of the Vector A and then we will divide the Vector A with the magnitude to find the unit vector parallel to Vector A.

Hence, the magnitude of Vector A = $\sqrt{3^2+6^2+2^2}$

Magnitude of A = $\sqrt{9 + 36+4}$

Magnitude of A = $\sqrt{49}$

Magnitude of A = 7

Now, the unit vector parallel to A = $\frac{3 i + 6 j-2k}{7}$

Hence, the unit vector parallel to vector A is:

= $\frac{3 i + 6 j-2k}{7}$