Find the unit vector perpendicular to A =3i +2j - k and B= i - J + k
Answers
Answered by
4
first take the cross product
A*B = C = 3i-4j-5k
to get the unit vector divide C by its modulus
c = C/sqrt(50)
A*B = C = 3i-4j-5k
to get the unit vector divide C by its modulus
c = C/sqrt(50)
Answered by
4
The ans is -2i/22 -3j/22 -3k/22 is the unit vector perpendicular to A and B vectors
Have you ans if so reply me.
Hope it will help you.
Have you ans if so reply me.
Hope it will help you.
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Harsharora0:
Sorry ans is wrong I ll send you the right.
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