find the unit vector perpendicular to the vectors
ā= 4^i-3^j+3^k
b= -2^i+^j-2^k
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Explanation:
dear
a vector perpendicular to the both of the given vectors can be found out by finding the cRoss products of the two vectors.
A=(3i+j+2k ) × (2i-2j+4k.) = 8i -8j -8k
unit vector =A /A| = 8i -8j -8k ) /√ (8 square +8 square +8 square ) = (i-j-k) /√3.
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Answer:
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