Find the units digit of the number (1! x 2! x 3!) + 4! + 2!?
Select one:
O a. 5
b.4
O c.3
O d. 8
Answers
Answered by
2
Answer:
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Answered by
0
The correct answer is option (d) 8
Given:
(1! x 2! x 3!) + 4! + 2!
To find:
The units digit of the number (1! x 2! x 3!) + 4! + 2!
Solution:
As we know n! = 1 × 2 × 3 × 4.... n times (the product of n natural numbers)
⇒ 1! = 1 = 1
⇒ 2! = 2 × 1 = 2
⇒ 3! = 3 × 2 × 1 = 6
⇒ 4! = 4 × 3 × 2 × 1 = 24
From above values
(1! x 2! x 3!) + 4! + 2! = (1 × 2 × 6) + 24 + 2
= 12 + 26 = 38
Here, unit digit of 38 is 8
Therefore, (1! x 2! x 3!) + 4! + 2! = 38
⇒ Units digit of the number (1! x 2! x 3!) + 4! + 2! is 8
The correct answer is option (d) 8
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