Find the unknown angle x and y in each of the following figures...plz give answer in step by step explanation...correct answer will be marked BRAINLIEST and be followed...✌
Answers
Step-by-step explanation:
Let the point where the diagonals bisect Be O.
Since ZY || WX,
Angle ZYW = Angle YWX = 28° ( Alternate interior angles)
In Triangle OWX,
Angle OWX + Angle OXW + x = 180°
(Angle sum property of a Triangle)
=> 28° + 40° + x = 180°
=> 68° + x = 180°
=> x = 180°- 68°
=> x = 112°
Since ZW || YX,
Now, Angle ZWY = WYX = 43° (Alternate Interior angles)
So, y + Angle ZWY + Angle OWX = 180°
{Linear Pair}
=> y + 43° + 28° = 180°
=> y = 180° - (43° + 28°)
=> y = 180° - 71°
=> y = 109°
Therefore x = 112° and y = 109°
Answer:
x = 112° and y = 109°
Step-by-step explanation:
LET THE MIDDLE POINT BE O.
SINCE ZY//WX, ∠ZYX +∠YXW = 180°
⇒ 28° + 43° + 40° + ∠ZXY = 180°
⇒ ∠ZXY = 180° - 111° =69°
IN ΔXOY, ∠XOY + ∠ OYX +∠YXO = 180°
⇒∠XOY = 180° - (43 + 69)° = 180° - 112° = 68°
WOY IS A STRAIGHT LINE, SO, x +68° = 180° ⇒ x = 112°
SINCE ZW//YX, y = ∠YXW = 40° + 69° = 109°