Find the unknown angles in the following figure.
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Answered by
1
Answer:
the correct answer of this question is 55° .
Step-by-step explanation:
since , AB II ED and AE is transversal, So,
angle AED = ANGLE EAF = 95°
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Answered by
1
Answer:
ED|| AB
angle DEA + angle EAB = 180° ( by co - interior angle)
angle EAB = 180 ° - 95°
angle EAB = 85°
In ∆ ABC,
angle EAB + angle ABC + angle BCA = 180 °
( by triangle some property)
85° + angle ABC + 40 ° = 180 °
angle ABC = 180 ° - 85° - 40 °
angle ABC = 180° - 125°
angle ABC = 55°
x = 55°
angle EAB + y = 180° ( linear pair)
y ° = 180 ° - 85 ° ( angle EAB = 85° )
y = 95°
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