Math, asked by sumanshivani99, 4 months ago

Find the unknown angles in the following figure.​

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Answers

Answered by mrvineet99
1

Answer:

the correct answer of this question is 55° .

Step-by-step explanation:

since , AB II ED and AE is transversal, So,

angle AED = ANGLE EAF = 95°

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Answered by laxmidevi756225
1

Answer:

ED|| AB

angle DEA + angle EAB = 180° ( by co - interior angle)

angle EAB = 180 ° - 95°

angle EAB = 85°

In ∆ ABC,

angle EAB + angle ABC + angle BCA = 180 °

( by triangle some property)

85° + angle ABC + 40 ° = 180 °

angle ABC = 180 ° - 85° - 40 °

angle ABC = 180° - 125°

angle ABC = 55°

x = 55°

angle EAB + y = 180° ( linear pair)

y ° = 180 ° - 85 ° ( angle EAB = 85° )

y = 95°

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