Find the unknown angles in the following
Figures
280
(4-6)
420
(x+5)
Answers
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2
(i) In Fig (i),
x = y (Angles opposite to equal sides)
But x + y + 80° = 180° (Angles of a triangle)
⇒ x + x + 80° = 180°
⇒ 2x = 180° - 80° = 100°
⇒ x = 100°/2 = 50° ∴ y = x = 50°
Hence x = 50°, y = 50°
(ii) In Fig. (ii),
b = 40° (Angles opposite to equal sides)
But a + b + 40° = 180°
(Angles of a triangle)
⇒ a + 40° + 40° = 180°
⇒ a + 80° = 180°
⇒ a = 180° - 80° = 100°
Hence, a = 100° , b = 40°
I am not sure but I think this is the answer.
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