Find the unknown angles in the given triangle
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Solution!!
Mark the ∠a and ∠b, as shown in the attachment.
∠a + 120° = 180° (Linear pair)
∠a = 180° - 120°
∠a = 60°
∠a = ∠b because the sides are equal. If the sides are equal, then the angles are also equal.
∠a = ∠b = 60°
∠b + ∠y = 180° (Linear pair)
60° + ∠y = 180°
∠y = 180° - 60°
∠y = 120°
The sum of all angles of triangle is 180°.
∠a + ∠b + ∠x = 180° (Angle sum property of triangle)
60° + 60° + ∠x = 180°
120° + ∠x = 180°
∠x = 180° - 120°
∠x = 60°
∠y + 25° + ∠z = 180° (Angle sum property of triangle)
120° + 25° + ∠z = 180°
145° + ∠z = 180°
∠z = 180° - 145°
∠z = 35°
The unknown angles x, y and z are 60°, 120° and 35°, respectively.
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