Question

Find the unknown length.

Answer 1

Hey!!
Here is the answer..

Let the given triangle be named as $\triangle{ABC}$

Now,
AB = 8 cm
BC = 15 cm
We have to find 'x',
x = AC = ?

Now,
$\angle{ \: ABC \: } = 90 {}^{0}$
Hence,
By Pythagoras theorem,

${AB}^{2} + {BC}^{2} = AC {}^{2}$

$\textbf{8}^{2} + \textbf {15}^{2} = \textbf{x} {}^{2} \\ \textbf{ 64 + 225} = \textbf x {}^{2}$

$\textbf{289} = \textbf{x}^{2} \\ \sqrt{289} = \textbf{x} \\ \textbf{17} = \textbf{x }$

Hence ,
x = 17 cm

I hope my answer helped!!

Answer 2

Answer:

Hey!!

Here is the answer..

Let the given triangle be named as \triangle{ABC}△ABC

Now,

AB = 8 cm

BC = 15 cm

We have to find 'x',

x = AC = ?

Now,

\angle{ \: ABC \: } = 90 {}^{0}∠ABC=900

Hence,

By Pythagoras theorem,

{AB}^{2} + {BC}^{2} = AC {}^{2}AB2+BC2=AC2

\begin{lgathered}\textbf{8}^{2} + \textbf {15}^{2} = \textbf{x} {}^{2} \\ \textbf{ 64 + 225} = \textbf x {}^{2} \\\end{lgathered}82+152=x2 64 + 225=x2

\begin{lgathered}\textbf{289} = \textbf{x}^{2} \\ \sqrt{289} = \textbf{x} \\ \textbf{17} = \textbf{x }\end{lgathered}289=x2289=x17=x 

Hence ,

x = 17 cm

I hope my answer helped!!