FIND THE UNKNOWN MARKED ANGLES ALSO GIVE REASONS
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Answer:
x = 60
x = 60 y = 60
x = 60 y = 60y= 60
Explanation
Since , BD is a strength line
so , by linear pair axiom
angle ACB + Angle ACD = line BCD
x + 120° = 180°
( Transferring 120° to RHS )
x = 180°-120°
x=60°
we know that , sum of all angles of triangle is 180°
so , by angle sum property of triangle
angle ABC + angle BAC + Angel ACB = 180°
y+y+x = 180°
2y + x = 180°
2y + 60° = 180 °
( Transferring 60° to RHS )
2y = 180°-60°
2y = 120°
( Transferring 2 to RHS )
y = 120°/2
y= 60°
or
we know that , exterior angle of triangle is equal to the sum of two interior opposite angles
so , angle ABC + Angle BAC = 120°
y + y = 120°
2y= 120°
( Transpering 2 to RHS )
y = 120/2
y = 60 °
Hope this will help you
thanks
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