Question

FIND THE UNKNOWN MARKED ANGLES ALSO GIVE REASONS

Answer 1

Answer:

x = 60

x = 60 y = 60

x = 60 y = 60y= 60

Explanation

Since , BD is a strength line

so , by linear pair axiom

angle ACB + Angle ACD = line BCD

x + 120° = 180°

( Transferring 120° to RHS )

x = 180°-120°

x=60°

we know that , sum of all angles of triangle is 180°

so , by angle sum property of triangle

angle ABC + angle BAC + Angel ACB = 180°

y+y+x = 180°

2y + x = 180°

2y + 60° = 180 °

( Transferring 60° to RHS )

2y = 180°-60°

2y = 120°

( Transferring 2 to RHS )

y = 120°/2

y= 60°

or

we know that , exterior angle of triangle is equal to the sum of two interior opposite angles

so , angle ABC + Angle BAC = 120°

y + y = 120°

2y= 120°

( Transpering 2 to RHS )

y = 120/2

y = 60 °

Hope this will help you

thanks