Question

find the unknown
rectangle::area=(x-4)(x+3)÷3x-12
length=x-3÷3 breadth=?
triangle::base=(x+y)(x-y) (x>y)
altitude=2(x+y)÷x-y area=?

Answer 1

Answer:

breath = x+3/x-3units area of triangle =x^2+2xx+y^2 sq units

Step-by-step explanation:

l*b=area of rectangle

x-3/3*b=(x-4)*(x+3)/3x-12

x-3/3*b=(x-4)*(x+3)/3(x-4)

x-3/3*b=(x+3)/3

(x-3)*b=x+3

b=x+3/x-3

area of triangle=1/2*altitude*base

area of triangle=1/2*2(x+y)/(x-y)*(x+y)(x-y)

area of triangle=1*(x+y)^2

area of triangle=x^2+2xy+y^2