Find the unknown sizes of angles
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linear pair on line BCD i.e. angle ACB+ angle ACD.
= therefore. x+ 110°= 180°
= x=180-110
= x= 70° ...
now we know that, sum of exterior angle is equal to sum of two interior angles ........
also, AB=AC hence, angle y= angle x
so, angle Y= 70°
NOW ANGLE SUM PROPERTY IN TRIANGLE ABC.
X+Y+Z= 180°
70°+70°+Z= 180°
Z= 180-140
Z= 40°
HENCE ALL ANGLES ARE FOUND........
ANGLE X= 70°
ANGLE Y= 70°
ANGLE Z= 40°
HOPEFULLY IT WILL WORK.......
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