Math, asked by suprenalama123, 6 months ago

Find the unknown sizes of angles ​

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Answers

Answered by J1234J
1

Answer:

115°=x°

65+x=180

x=180-65

x=115°

Answered by bighnes87
1

{\huge{\pink{\underbrace{\overbrace{\mathbb{\blue{ANSWER:-}}}}}}}

As ΔPQR is a isosceles triangle with RP=RQ

So,

∠RQP=∠RPQ

∠RPQ=65°

We know, two angles of a triangle add up to the opposite external angle

So,

∠RQP+∠RPQ= x

65+65=x

\huge\boxed{\red{x=130}}

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