Question

Find the unknown sizes of angles in the following figures.​

Answer 1

A=45, and

A=45, andB=45.

as the angle opposite to equal sides are equal

so then,

so then,A=B

so then,A=Bthen,

so then,A=Bthen, 90+A+B=180

so then,A=Bthen, 90+A+B=18090+2A=180

so then,A=Bthen, 90+A+B=18090+2A=180then A=45

so then,A=Bthen, 90+A+B=18090+2A=180then A=45as b=a,

so then,A=Bthen, 90+A+B=18090+2A=180then A=45as b=a,b=45

so then,A=Bthen, 90+A+B=18090+2A=180then A=45as b=a,b=45❤❤❤❤HOPE IT HELP YOU

so then,A=Bthen, 90+A+B=18090+2A=180then A=45as b=a,b=45❤❤❤❤HOPE IT HELP YOU STAY SAFE❤❤❤❤

Answer 2

Answer:

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Find the angles in the following figure..?

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Given:-

XY = YZ

Angle XYZ = 90°

To Find :-

Angle A and Angle B

Solution:-

Angle A = Angle B ( Angles opposite to equal sides are equal)

So In Triangle XYZ (by Angle Sum Property)

Angle X + Angle Y + Angle Z = 180°

=> b + 90° + a = 180°

=> a + 90° + a = 180° ( Angle a = Angle b )

=> 2a + 90° = 180°

=> 2a = 180° - 90°

=> 2a = 90°

=> a = 90°/2

=> a = 45°

So, Angle A = Angle B = 45°