find the unknown x of the triangle of this figure
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Answer:
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Answer:
i) By using angle sum property of triangle
\angle A+\angle B+\angle C\ =\ 180\degree∠A+∠B+∠ = 180°
x+50\degree+60\degree=\ 180\degreex+5+6= 180°
x\ =\ 180\degree-\ 110\degreex = 18− 110°
x\ =\ 70\degreex = 70°
(ii) By using angle sum property of triangle
\angle P+\angle Q+\angle R=\ 180\degree∠+∠+∠= 180°
90\degree+30\degree+x\ =\ 180\degree90+30+x = 180°
x=\ 180\degree-120\degreex= 180−120°
x\ =\ 60\degreex = 60°
(iii) By using angle sum property of triangle
\angle X+\angle Y+\angle Z\ =\ 180\degree∠+∠+∠Z = 180°
30\degree+\ 110\degree+x=\ 180\degree30+ 110°+x= 180°
x\ =\ 180\degree-140\degreex = 180°−140°
x\ =\ 40\degreex = 40°
(iv) By using angle sum property of triangle
\angle A+\angle B+\angle C=\ 180\degree∠A+∠B+∠C= 180°
50\degree+\ x+x\ =\ 180\degree50°+ x+x = 180°
50\degree+\ 2x\ =80\degree50°+ 2x =80°
x\ =\ \frac{130}{2}x = 2130
x\ =\ 65\degreex = 65°