Find the unknowns A, B and C if Ax² – Bx + B + 1 ≡ (x – 2)(x + C)
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Answer:
A=1, B=5, C= -3
Step-by-step explanation:
Ax² – Bx + B + 1 ≡ (x – 2)(x + C)
Ax² – Bx + B + 1 ≡ x² + Cx - 2x - 2C
Ax² – Bx + B + 1 ≡ x² + (C - 2)x - 2C
Comparing LHS and RHS,
A = 1
B = 2 - C
B+1 = -2C
2-C+1=-2C
C=-3
B=2-(-3)=5
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