Math, asked by chandramanibdk2019, 4 months ago

FIND THE VAIUE OF N: 8×2^n+2=32​

Answers

Answered by adityakumarsingh1002
2

Step-by-step explanation:

8x2^n+2=32

2^3x2^n+2=32

2^3+n+2=32

2^5+n=32

2^5+n=2^5

5+n=5

n=0

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Answered by xSoyaibImtiazAhmedx
1

\huge\underline{\overline{\mid\star{\sf{\pink{Solution}}\star\mid}}}

8 \times  {2}^{n + 2}  = 32 \\  =  > {2}^{3}  \times  {2}^{n + 2}  =  {2}^{5}  \\  =  >  {2}^{n + 2 + 3}  =  {2}^{5}  \\  =  >  {2}^{n + 5}  =  {2}^{5 }  \\  =  > n + 5 = 5 \\  =  > n = 0

When n=0,

8× {2}^{n + 2}  = 8 \times  {2}^{0 + 2}   \\  = 8  \times  {2}^{2}  = 8 \times 4 \\  = 32

\bold{\boxed{The\: value\: of\: n\:is 0}}

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