Question

Find the vale of 4(sec²59*-cot²31)/3-2sin90*+3tan²56*×tan²34 = x/4

Answer 1

Given 4(sec2 59°-cot231)/3-2/3 Sin 90°+tan256xtan234 = (x/3)
(x/3) = 4[sec2 (90° – 31°) - cot231)/3] - 2/3 (1) + tan2(90° – 34°) x tan234
(x/3) = 4[cosec2 31° - cot231°)/3] - 2/3 + cot2 34° x tan234
(x/3) = 4[1]/3 - 2/3 + 1
(x/3) = 4/3 - 2/3 + 1
(x/3) = 2/3 + 1 = 5/3
Hence x = 5