Question

Find the vale of k for which root of the equation x2-8kx+2k=0 are real and equal

Answer 1

For equal roots

d = 0

b²-4ac = 0

(-8k)² - 4(1)(2) = 0

64k² -8 =0

64k² = 8

k² = 8/64

k² = 1/8

k = ±1/2