find the vale of k so that the points (k,2-2k),(-k+1,2k) and (-4-k,6-2k) are colliner
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Answer:
Step-by-step explanation:
For collinear points, area of triangle formed by
them is ZERO
Area can be find out by determinant
(See attachment)
On solving the quadratic equation,
WE GET
→ K= -1 or K= 1/2
Attachments:
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