Question

Find the vale of p,p in each of the following: 1. log,base,2,32,equals ,p,LOG2 32=p. 2. base,p,81,equals,2,LOGp81=2​

Answer 1

Given  :  log₂32=p  

$\log_p81=2$

To Find : Value of p

Solution:

log₂32=p  

=>  log₂2⁵=p  

log aⁿ  = n log a

=>  5 log₂2 =p  

logₐa= 1

=>  5 ( 1) = p

=> p = 5

$\log_p81=2$

Dividing both sides by 2

=>  $\frac{1}{2} \log_p81=1$

=>  $\log_p81^{\frac{1}{2} }=1$

=>  $\log_p9=1$

=> p = 9

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Answer 2

Answer:

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