Question

find the vale of P(x)=2x³+x²-X-1 at x=-2.​

Answer 1

Answer:

P(-2)=2(-2)³+(-2)²-(-2)-1

=2(-2×-2×-2)+(-2×-2)+2-1

=2(4×-2)+4+1

=2(-8)+5

=-16+5

= -11

Answer 2

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find the vale of P(x)=2x³+x²-X-1 at x=-2.

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$p(x) = 2{x}^{3} + {x}^{2} - x - 1$

$x = - 2$

$p( -2) = 2 {( - 2)}^{3} + {( - 2)}^{2} - ( - 2) - 1$

$p( - 2) = 2( - 8) + 4 + 2 - 1$

$p( - 2) = 6- 17$

$p( - 2) = - 11$

${\boxed {\boxed{ =-11}}}$

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